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45^2+x^2=83^2
We move all terms to the left:
45^2+x^2-(83^2)=0
We add all the numbers together, and all the variables
x^2-4864=0
a = 1; b = 0; c = -4864;
Δ = b2-4ac
Δ = 02-4·1·(-4864)
Δ = 19456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19456}=\sqrt{1024*19}=\sqrt{1024}*\sqrt{19}=32\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{19}}{2*1}=\frac{0-32\sqrt{19}}{2} =-\frac{32\sqrt{19}}{2} =-16\sqrt{19} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{19}}{2*1}=\frac{0+32\sqrt{19}}{2} =\frac{32\sqrt{19}}{2} =16\sqrt{19} $
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